What is the equation of the line that has an x-intercept of x=2.5 and y-intercept of y=1.5?​

y = -3/5x + 3/2

Step-by-step explanation:

begin with the slope-intercept form of a line which is:  y = mx + b

'm' is the slope and 'b' is the y-intercept

the y-intercept is given but we need to find the slope

we can do so by using the points created by the x-and-y intercepts:

(0, 3/2) and (5/2, 0)  

3/2 ÷ -5/2 = -3/5 (slope)

y = -3/5x + 3/2

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

answer: i believe the answer is e

step-by-step explanation: