Find the angle (if it exists) in the interval [0, 2 ) for which sin = cos

θ = π/4 over the interval [0,2)

Step-by-step explanation:

sinθ=cosθ

sinθ/cosθ=1

tanθ=1

θ = π/4 + πn

Because the domain is restricted to the interval [0,2) the only angle that exists which satisfies the interval is π/4. See the graph for a visual.

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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