A triangle has vertices P(−5, 4), Q(3, 4), and R(−5, −2). S is the midpoint of Segment PQ and T is the midpoint of Segment PR. What is the length of Segment ST? Segment ST equals six square root of two end square root
Segment ST equals four
Segment ST equals three square root of two end square root
Segment ST equals five

Length of ST = mQR/2 = 4

Step-by-step explanation:

S and T are the mid-points of PQ and PR, so ST is parallel to and equal to half the length of QR.

(following corrected due to mistake)

Length of QR = sqrt((3--5)^2+(4--2)^2)=sqrt(8^2+6^2)=10

Length of ST = mQR/2 = 5

I apologize for the error previously committed.

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below:

it is a. 4.2 because 7.6-3.4 gets the remaining length of 4.2. i might be wrong but i am pretty sure this is the answer.