M is the midpoint od AN, A has coordinates (-4,-4), and M has coordinates (-7,1). Find the coordinates of N

Since M is the Midpoint.

M(-7,1)

A(-4,-4) N(x,y)

From Midpoint Formula

-7 = -4 + x/(2)

-14=-4+x

x=-10

1=-4+y/2

2=-4+y

y=6.

N has the points (-10,6).

Hope this helps!

Solution given:

A(x1,y1)=(-4,-4)

M(x,y)=(-7,1)

N(x2,y2(x,y) let

we have

midpoint(x,y)={(x1+x2)/2,(y1+y2)/2}

(-7,1)={(-4+x)/2,(-4+y)/2} comparing corresponding value

-7=(-4+x)/2

-14=-4+x

x=-14+4

x=-10

and

1=(-4+y)/2

2=-4+y

y=4+2

y=6

coordinates of N is (-10,6)

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1