Put the quadratic into vertex form and state the coordinates of the vertex. y= y= \,\,x^2-6x-3 x 2 −6x−3

Step-by-step explanation:

Given

Solving (a): In vertex form

The vertex form of an equation is:

To do this, we make use of completing the square method.

We have:

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Take the coefficient of x (i.e. -6)

Divide by 2; -6/2 = -3

Square it: (-3)^2 = 9

Add and subtract the result to the equation

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Factorize

Factor out x - 3

Express as squares

Hence, the vertex form of is:

Solving (b): State the coordinates of the vertex.

In ; the vertex is: (h,k)

The vertex of will be

step-by-step explanation: