What is the equation of the line that passes through the given point and is perpendicular to the given line? Point: (1,1)
Line: y=1/5x+4/5

Step-by-step explanation:

Hey there!

The equation of a line which passes through the point (1,1) is (y-1) = m1 (x-1)(i) {using one point formula}

Also, another equation which is perpendicular to the line is y = 1/5 x + 4/5(ii)

Comparing equation (ii) with y= mx+c, we get;

Slope (m2) = 1/5.

Now, As per the condition of perpendicular lines,

m1*m2 = -1

or, m1 * 1/2 = -1

or, m1= -2

Therefore, m1 = -2.

Keeping the value of m1 in equation (i) we get;

y-1 = -2(x-1)

y-1 = -2x+1

or, y+2x-2= 0

Therefore, the required equation is 2x+y-2= 0.

Hope it helps!

option: d is the correct answer.

d) none of the above.

step-by-step explanation:

clearly from the figure attached to the question we could see that there is no shape given. hence without any shape given in the figure and after rotation we can't obtained a square pyramid.

since, to obtain a image we need a proper figure of the pre-image so that it can be transformed.

hence, the correct answer is:

d) none of the above.

step-by-step explanation:

i think the answer is b