Q1) 104m²
Q2) 121 in.²
Step-by-step explanation:
Q1)
GIVEN :-
Figure given in the question comprises of a triangle & a rectangle.Length of the rectangle = 10 mWidth of the rectangle = 8 m Base of the triangle = 8 mHeight of the triangle = 6 m
TO FIND :-
Area of the figure
GENERAL FORMULAES TO BE USED IN THIS QUESTION :-
For a triangle with height 'h' & base 'b' , its area =
.For a rectangle with length 'l' & width 'w' , its area =
SOLUTION :-
Area of the triangle = 
Area of the rectangle = 
Area of the figure = (Area of the triangle) + (Area of the rectangle)
= 24m²+ 80m²
= 104m²
Q2)
GIVEN :-
Figure given in the question comprises of a triangle & a trapezium.Lengths of parallel sides of trapezium are 6 in. & 7 in. Height of trapezium = 20 - 3 = 17 in.Base of the triangle = 3 in.Height of the triangle = 7 in.
TO FIND :-
Area of the figure
GENERAL FORMULAES TO BE USED IN THIS QUESTION :-
For a triangle with height 'h' & base 'b' , its area =
.For a trapezium with parallel sides whose lengths are 'a' & 'b' and height 'h' , its area =
SOLUTION :-
Area of the triangle = 
Area of the trapezium = 
Area of the figure = (Area of the triangle) + (Area of the trapezium)
= 10.5 in.² + 110.5 in.²
= 121 in.²
