Find xy if x + y=3, x^2 + y^2 = 5

mark me

Step-by-step explanation:

x+y=3

x=3-y

putting the value of x

in this

x²+y²=5

(3-y) ²+y²=5

9-6y+y²+y²=5

2y²-6y+9-5=0

2y²-6y+4=0

2y²-4y-2y+4=0

2y(y-2)-2(y-2)=0

(2y-2) (y-2) =0

2y-2=0 or y-2=0

y=1 or y=2

so x=2 or 1

so x×y=2×1 or 1×2=2

I HOPE THIS WILL HELP YOU MARK ME BRAINLIEST

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)