Compute the double integral ∫∫D 5xy²dxdy

over the region D bounded by

xy=1, xy=16, xy²=1, xy²=36

in the first quadrant of the xy-plane. Hint: make a change of variables T:R2→R2 that converts a rectangular region D∗ in the uv-plane into the region of integration D=T(D∗) in the xy-plane.

Double integral =

what is the question? i am guessing you are looking for the area.

to find an area, you have to do length x width.

in this case, it would be 12 ft x 4 ft = 48 sq. ft

could u provide us some answer choices or hmm idk maybe a table for us to anser with ? ?

10+4√2 is the answer. i dont have the time to explain.