A bag contains 5 yellow balls 3 red balls and 2 green balls. A ball is removed from the bag without looking, the colour recorded, and then returned the bag. A second ball is drawn and its colour is also recorded. c) What would be the outcome of the 2 balls if it has a probability of 1/10?

the two balls are yellow and green, in either order.

Step-by-step explanation:

P(Y) = 5/10 = 1/2

P(R) = 3/10

P(G) = 2/10

Since the only combination that makes a product of 1/10, so

P(Y)*P(G) = (5//10) * (2/10) = 10/100 = 1/10

So the two balls are yellow and green, in either order.

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

1/8 3/16 3/4

step-by-step explanation:

you put them as all the same denominator and multiply