X^2=6x+1 rewrite the equation by completing the square your equation should look like (x+a)^2=b or (x-c)^2=d

What are the solutions to the equation?

sdsWD

Step-by-step explanation:

SDDQd

x=3+√10 or x=3−√10

Let's solve your equation step-by-step.

x2=6x+1

Step 1: Subtract 6x+1 from both sides.

x2−(6x+1)=6x+1−(6x+1)

x2−6x−1=0

For this equation: a=1, b=-6, c=-1

1x2+−6x+−1=0

Step 2: Use quadratic formula with a=1, b=-6, c=-1.

x= −b±√b2−4ac

2a

x=

−(−6)±√(−6)2−4(1)(−1)

2(1)

x=

6±√40

2

x=3+√10 or x=3−√10

pentagon

step-by-step explanation:

the coordinates   a(5, -2), b(3,-1),c(-4,-4) d(-3,8) and e(-1,4) forms the vertices of the polygon when they are connected in order.

in order to classify that which polygon is it with the given coordinates, first count the number of vertices and then count the number of sides it can make with these vertices.

since, the given coordinates have five vertices, therefore, it will make five sides. moreover, pentagon is regular in nature therefore it will be convex.

now, a polygon with five sides is known as pentagon, therefore, the given polygon is the pentagon.