What is the distance between the points (10, 2) and (14,5)?

hello, →

√

(

14

−

10

)

2

+

(

5

−

2

)

2

→

√

(

4

)

2

+

(

3

)

2

→

√

¯¯¯¯¯¯¯¯¯¯¯

16

+

9

→

√

¯¯¯¯

25

⇒

5

→

√

(

14

−

10

)

2

+

(

5

−

2

)

2

→

√

(

4

)

2

+

(

3

)

2

→

√

¯¯¯¯¯¯¯¯¯¯¯

16

+

9

→

√

¯¯¯¯

25

⇒

5 It is 5 btw

Step-by-step explanation:

e.

step-by-step explanation:

because there are always 10 numbers in a phone number.

18 units²

step-by-step explanation:

first let's find altitude bd using the distance formula

d = √((y₂ - y₁)² + (x₂ - x₁)²)

bd = √((0 - -3)² + (0 - 3)²)

bd = √18

given the placement of points a and c, we can denote that point d bisects segment ac.

we will call ac the base.

using the distance formula

ac = √((0 - 6)² + (-6 - 0)²)

ac = √72

knowing our base and our height, we can plug these into our triangle area formula

area = (b * h)/2

area = (√18 * √72) / 2

area = (√1296) / 2

area = 36 / 2

area = 18 units²