Find the principal that will yield a simple interest of Rs 9000 in 5 years at a rate of 6% per annum.

9514 1404 393

  ₹ 30000

Step-by-step explanation:

The simple interest formula is ...

  I = Prt . . . . . . principal P invested at rate r for t years

Fill in the values you know, and solve for the one you don't know.

  9000 = P(0.06)(5)

  9000/0.30 = P = 30000

The principal that will give ₹9000 in interest is ₹30000.

A =?

P= 9000

t = 5 yrs

r = 6% = 0.06

A = p(1+r)^t

A = 9000(1+0.06)⁵

A = 9000× 1.338

A = 12044 Rs.

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."