Given: AB and AC are congruent; AD is a perpendicular bisector of BC Prove: ∠B ≅ ∠C

Put the proof in order.
It is given that AB ≅ AC and that D is the midpoint of BC.
If ΔABD ≅ ΔACD, then ∠B ≅ ∠C by CPCTC.
AD is a shared side so AD ≅ AD by the reflexive property.
ΔABD ≅ ΔACD by SSS.
D is the midpoint of BC, so BD ≅ CD.