The cylinder is 40 feet tall and has a radius of 20 feet. The cone is 10 feet tall with the same radius. Approximately how many cubic feet of grain can fit in the silo?

54461.33 cubic feet

Step-by-step explanation:

Given data

Height of cylinder= 40 feet

Radius= 20feet

Height of cone= 10 feet

Radius of cone= 20feet

Volume of Cylinder= πr^2h

Volume of Cylinder= 3.142*20^2*40

Volume of Cylinder= 3.142*400*40

Volume of Cylinder= 50272 cubic feet

Volume of Cone= 1/3πr^2h

Volume of Cylinder= 1/3*3.142*20^2*10

Volume of Cylinder= 1/3*3.142*400*10

Volume of Cylinder= 1/3*12568

Volume of Cylinder=4189.33 cubic feet

Hence, the volume of the silo = volume of cylinder+ volume of cone

Volume of silo= 50272+4189.33

Volume of silo=54461.33 cubic feet

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c