Find the perimeter of triangle ABC with vertices A(–5, –2), B(–2, –2), and C(–5, 2).

12 units

Step-by-step explanation:

the perimeter = AB+AC+BC=

3+4+5 = 12

12 units

Step-by-step explanation:

AB = 3 units

BC = 5 units

CA = 4 units

Perimeter of triangle,

→ AB + BC + CA

→ 3 + 5 + 4

→ 12 units is the answer.

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

answer: 323 is how many she has ☃☃⛄❄

step-by-step explanation: