A circle in the xy-coordinate plane has the equation x2 + y2 +6y -4 = 0. If the equation of the circle is written in the form x2 + (y+k)2 = c. where k and care constants, what is the value of K?

k = 3

Step-by-step explanation:

Given

x² + y² + 6y - 4 = 0 ( add 4 to both sides )

x² + y² + 6y = 4

Using the method of completing the square

add ( half the coefficient of the y- term )² to both sides

x² + y² + 2(3)y + 9 = 4 + 9

x² + (y + 3)² = 13

with k = 3

i dont know nkw

step-by-step explanation:

kenffledkedncklzkdfeserw

the length of o'p' is .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

the scale factor is 1.5.

multiply both sides by op.

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is .