Given a box of 8 color crayons (Red, Blue, Green, Orange, Yellow, Brown, Black, Purple). If I remove a single crayon randomly, and without putting it back in the box, I remove a second crayon randomly, what is the probability that I will remove the Red and the Green crayon from the box

1/56

Step-by-step explanation:

Since the box has 8 different colors, the probability of picking any color of crayon will be 1/8.

This question relates to a probability without replacement, therefore, the probability of picking the red crayon first will be 1/8. After then, there'll be 7 crayons left and the probability of picking the green crayon next will be 1/7.

Therefore, the probability that I will remove the Red and the Green crayon from the box will be:

= 1/8 × 1/7

= 1/56

inequality:

620-37.4p ≥ 450

the minimum amount of packages needed to be removed from the elevator is 5.

step-by-step explanation:

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option