Given a box of 8 color crayons (Red, Blue, Green, Orange, Yellow, Brown, Black, Purple). If I remove a single crayon randomly, and without putting it back in the box, I remove a second crayon randomly, what is the probability that I will remove the Red and the Green crayon from the box

1/56

Step-by-step explanation:

Since the box has 8 different colors, the probability of picking any color of crayon will be 1/8.

This question relates to a probability without replacement, therefore, the probability of picking the red crayon first will be 1/8. After then, there'll be 7 crayons left and the probability of picking the green crayon next will be 1/7.

Therefore, the probability that I will remove the Red and the Green crayon from the box will be:

= 1/8 × 1/7

= 1/56

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47