There are 10 2/15 kg of watermelons and coconuts on a truck. The weight of the watermelons is 3 3/5 times that of the coconuts. How heavy are the coconuts on the truck, in kg?

2 7/76 kg

Step-by-step explanation:

Let the weight of

Watermelons = x

Coconut = y

There are 10 2/15 kg of watermelons and coconuts on a truck.

x + y = 10 2/15

x = 10 2/15 - y

x = 152/15 - y Equation 1

The weight of the watermelons is 3 3/5 times that of the coconuts.

x = 3 3/5 × y

x = 18/5 × y

x = 18y/5

How heavy are the coconuts on the truck, in kg?

Find y

We substitute 18y/5 for x in Equation 1

x = 152/15 - y

18y/5 = 152/15 - y

18y /5 + y = 152/15

Multiply through by 15

18y/5 × 15 + y × 15 = 152/15 × 15

3 × 18y + 15y = 152

54y + 15y = 152

69y = 152

y = 152/69

y = 2 14/152

y = 2 7/76 kg

Therefore, the weight of the coconuts are 2 7/76 kg

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !

the answer is d

hope this