What is the equation, in point-slope form, of the line that is parallel to the given line and passes through the point (-3, 1)?​

Step-by-step explanation:

Slope of the line drawn is -6 ÷ -4 =

Point slope is y - y1 = m(x - x1)

y1 = 1, x1 = -3

16.9 times 2.85

step-by-step explanation:

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°