(01.02 MC)Which of the following correctly uses absolute value to show the distance between -50 and 12? OT-50 - 12| = |-62] = -62 units
OT-50 + 12 = 1-38= 38 units
OT-50 + 12 = 1-38] = -38 units
OT-50 - 12| = |-62] = 62 units

Plz help

option D is correct. done

Choice D

|-50-12| = |-62| = 62 units

Explanation:

Draw out a number line. Mark two points on it at A = -50 and B = 12

The expression |A-B| represents the distance between the two points. So that would be

|A-B| = |-50-12| = |-62| = 62

Note that negative distance does not make sense. The smallest distance can get is 0. So the result of an absolute value problem is never negative.

Slightly alternative method:

If you wanted, you could plot point C on the number like such that C is at 0.

The distance from A = -50 to C = 0 is exactly 50 units

From C = 0 to B = 12 is an additional 12 units

Therefore, the total distance is AC+CB = 50+12 = 62 units

Side note: |A-B| is the same as |B-A|. The order of subtraction doesn't matter as long as you use absolute value. If absolute value wasn't there, then A-B is different from B-A.

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.

my computer is slow i can not see it sorry