During one month, the mean high temperature in Boise, Idaho, was 52.1°F with a standard deviation of 6.5° F. During the same month, the mean high temperature in Death Valley, California, was 81.9° F with a standard deviation of 6.4° F. Select all the statements that are true. ​

B. The average high temperature in Death Valley was greater than the average in Boise

C. The variation of high temperature in Death valley was about the same as the variation in Boise

Step-by-step explanation:

Step 1: In a normal distribution, about 95% of the values are ±2 standard deviations from the mean. ±2 standard deviation from the mean high temperature of Boise is 39.1 to 65.1. Therefore, option A is wrong

Step 2: The average temperature high temperature of each of the places isngiven by their mean high temperatures.

The mean high temperature in Boise, Idaho, was 52.1°F while the mean high temperature in Death Valley, California, was 81.9°F.

Difference between the mean high temperatures is (81.9 - 52.1) = 29.8°F

Therefore, the average high temperature in Death Valley was greater than the average in Boise. Option B is correct.

Step 3: Standard deviation measures how spread out data is. It is a measure of variation of data.

The standard deviation of the high temperature in Boise, Idaho was 6.5° F, while the standard deviation of the high temperature in Death Valley, California was 6.4° F. This two values are about the same. Therefore, option C is correct.

Step 4: In a normal distribution, about 68% of the values are ±1 standard deviations from the mean. ±1 standard deviation from the mean high temperature of Death Valley is 75.5 to 88.3. Therefore, option D is wrong

Step 5: In a normal distribution, about 99.7% of the values are ±3 standard deviations from the mean. ±3 standard deviation from the mean high temperature of Boise is 32.6 to 71.6. Therefore, option E is wrong

i believe it is c.y = 9x

rise over run. 9 units up over 1 unit right or 9/1