I will appreciate a quick answer please.
Factorize all of the following

(s+16)(s-16)

Step-by-step explanation:

s^2-256

s^2-(16)^2

a^2-b^2= (a+b)(a-b)

(s+16)(s-16)

1.      5 ( − 6 ) 2

2.     (−16)(+16)

3.     ( 7q-3r) ^2  

Step-by-step explanation:

5a^2 - 60a + 180   we factor 5 as multiple of a alone (outside of brackets)

Then we keep the common a with its number as 180 doesn't share a

Then we look solely for two numbers that add up to 60 and multiply to 180

We show in the first line what we found and then continue to factor the square of a in format of 5a^(2) and format of -6a-6a to find 5(a2−6a−6a+36) like below until its completed in factored form - 6 -6 would multiply to find +36 and -6-6 subtracts to find -12.

5a^2 - 60a + 180

5(  ^ 2 − 1 2 + 3 6)  

5 ( ^ 2 − 6 − 6 + 3 6 )

5(a^{2}-6a-6a+36)

5(a2−6a−6a+36)

5 ( ( − 6 ) − 6 ( − 6 ) )

5 ( − 6 ) ( − 6 )

5 ( − 6 ) 2

2.

s^2 - 256

2 + 1 6 − 1 6 − 2 5 6

(+16)−16(+16)

(−16)(+16)

3.  

49q^2 + 42qr + 9r^2

(7q )^2 + (7 x 6 + qr) + 3r^2  like by like = 7q and 3r as 3+3 = 6 when squared is our factor outside of brackets and we notice that 6 is not squared in rule.

( 7q-3r) ^2  

i dont know sorry

step-by-step explanation: