I really need help with these 3 questions plsss

#3.

Let's first make an equation out of the information given about Frank: y = -15x + 630.

Then, we can plug in 20 for x to find out how many bricks he has after 20 minutes.

-15(20) + 630 = 330

So, Frank has 330 bricks left after 20 minutes. If we look at the graph, find 20 minutes on the x-axis, and follow that up to where it meets with the line, we can see that Francis has only 320 bricks remaining after 20 minutes.

Therefore, Francis will have the fewest bricks left after 20 minutes.

#2.

First, we need a bit of information about both of the functions: the slope and y-intercept. The slope of function W is 1/2, and the y-intercept is -1. The slope of function Z is 1/4, and the y-intercept is -2. Now, let's take a look at the options.

1. False - 1/2 is greater than 1/4

2. True - 1/2 is greater than 1/4

3. False - -2 does not equal -1

4. False - -1 is greater than -2 (closer to 0)

5 & 6. False - The y-value when you plug -4 into function W is -3, and the y-value when you plug -4 into function Z is also -3.

#1.

This problem involves using the slope formula for functions A and B, and finding m in the equation for function C.

Slope of function A = 2

Slope of function B = 3/5

Slope of function C = 3

Therefore, in order from least to greatest is: B, A, C.

Hope this helps!! :)

ddd

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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