Professor Rosencrantz flips a fair coin once. Professor Guildenstern flips a fair coin three times. What is the probability that Professor Rosencrantz obtains more heads than Professor Guildenstern

9/13 = 0.6923

Step-by-step explanation:

We start by defining

A as event that head was flipped

B1 = event that coin is biased

B2 = event that it is unbiased

P(B1) = 3/5

P(B2) = 2/5

P(A|B1) = 3/4

P(A|B2) = 2/4 = 1/2

When we solve this using bayes theorem we have to find

p(B1|A) = [P(B1) x P(A|B1)]/[P(B1) x P(A|B1) + P(B2) x P(A|B2)

= 0.6 x 0.75 / 0.6 x 0.75 + 0.4x0.5

= 0.45/0.45+0.2

= 0.45/0.65

= 0.6923

please brainliest

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

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