Tobias is constructing barriers to prevent cars from driving on a bike path. He can make conical pylons using the dimensions shown. If he used the same amount concrete to construct a spherical barrier, how tall would it be? Use 3.14 for and round your answer to the nearest tenth of a foot. PLS HELPPP !

1.6 ft.

Step-by-step explanation:

Given that the conical pylons had a radius (r) of 1 foot and a height (h) of 2 foot. The volume of the conical pylons is:

Volume = πr²h/3

Therefore substituting gives:

Volume = π(1)²(2)/3 = 2π/3 ft³

Since the same amount of concrete is used to construct a spherical barrier, hence the volume of the sphere would be the same as the volume of the conical pylon.

Volume of sphere = 4πr³/3

4πr³/3 = 2π/3

2r³ = 1

r³ = 1/2 = 0.5

r = ∛0.5 = 0.8 ft.

Therefore the radius of the spherical barrier would be 0.8 ft. and the height would be 2r = 2(0.8) = 1.6 ft.

6. 104

7. 52/37

8. 2704

9. 140608

10. -52

11. |52|=52

12. 1/52

13. 156

14. 26

15. 40

16. 37

17. -364

18. 53 1/3

19. 50.96

20. 43 2/3

21. 78

22. 50.75

23. 47.63

24. 163.28

25. 10400

26. 338

27. 208

28. 2704 square inches

29. 312 square meters

30. don't know what its asking, tell me so i can tell you

31. 8490.56

32. 52 degrees would be an acute angle

33. 128 degrees

34. 20.8

35. 39

36. 208

30.5*10=350$

you have to multiply the number without the decimal point then add it later but if its tenn u must move the place value of the decimal point 1 to the right.