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x+2y= -10eqn(i)

3x-y=12eqn(ii)

multiply the eqn(ii) by 2

x+2y= -10

6x-y=12

or, 7x=14

or, x=14/7

or, x=2

now, substituting the value of x=2 in eqn(i)

x+2y= -10

or, 2+2y= -10

or, 2y= -10-2

or, 2y= -12

or, y= -12/2

or, y= -6

therefore the equation is proved

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)

p

step-by-step explanation: