What is the equation of the line that passes through the point (1, 3) and is perpendicular to the line 2x+3y=15?

y=2x+1

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Rearrange 2x+3y=15 by subtracting 2x by both sides. Dividing 3y by both sides.

1⇒

2⇒

We know this slope is negative. Meaning for the perpendicular crossing to work, it must have a positive slope. We know that 3=(1*M)+B. Perpendicular lines will have slopes that are negative reciprocals of one another.

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We know the slope must be between 1 and 3. We know the base must be between 1 and 3.

Using the slope formula y-y/x-x