A cylinder and a cone have the same volume. The cylinder has radius x and height y . The cone has radius 1/2x . Find the height of the cone in terms of y .

height = 1/4y

Step-by-step explanation:

V(cylinder) = πr²h

V(cone) = πr²h ÷ 3

V(cyl) = πx²y

V(cone) = π(1/2x)²y which simplifies to be πx²y ÷ 4

πx²y = πx²y ÷ 4

if you divide each side by πx² you get:

y = y/4

height is 1/4y

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

where is the picture

step-by-step explanation: