Jordan’s Cat Fern is a finicky eater. Jordan is trying to determine which of two brands of canned cat food Fern prefers.

There is significant difference in difference in the amount of food ferns eat ; and the preferred is TAB-a-cat.

(0.216, 5.984)

Step-by-step explanation:

This is a 2 sample t test test problem :

The hypothesis :

H0 : μ1 = μ2

H1 : μ1 ≠ μ2

x1 = 85.2 ; x2 = 82.1 ; n1 = 31 ; n2 = 30 ; s1 = 3.45 ; s2 = 4.62

The test statistic :

T = (x1 - x2) / √(s1²/n1 + s2²/n2)

T = (85.2 - 82.1) / √(3.45²/31 + 4.62²/30)

T = 3.1 / 1.0466

T = 2.96

Using the Pvalue from Tstatistic calculator :

df = smaller n - 1 = 30 - 1 = 29

Pvalue(2.96, 29) = 0.006075

α = 0.05

Pvalue < α ; We reject the Null and conclude that there is significant difference in difference in the amount of food ferns eat.

99% Confidence interval :

The test statistic :

(x1 - x2) ± Tcritical *√(s1²/n1 + s2²/n2)

Tcritical at 99% = Tcritical(0.01, 29) = 2.756

(85.2 - 82.1) / 2.756*√(3.45²/31 + 4.62²/30)

3.1 ± 2.8844296

Lower boundary = (3.1 - 2.8844296) = 0.216

Upper boundary = (3.1 + 2.8844296) = 5.984

(0.216, 5.984)

Since interval does not contain 0, then, we reject the Null.

b

step-by-step explanation:

no this is a nonlinear negative