Task: In this task you will help a farmer design the largest possible enclosure for her sheep. You will produce models (drawn) of your proposed enclosures as well as provide any supporting calculations. A farmer wants to build an enclosure to keep her sheep safe. The fencing comes in 1-meter segments. She has 300 segments available. What are the dimensions that maximize the area of her enclosure under the following constraints ​

1260=3*6*7*10=3^2*2^2*7*5 perfect cude = 3^3*2^

step-by-step explanation:

1. 16.64

a^2+b^2=c^2

pr^2=pq^2+qr^2

pr^2=14^2+ 9^2

pr^2=196+81

pr= sqr root of 277

16.64

2. 11.31

c^2-a^2=b^2

18^2- 14^2=b^2

b^2=324-196

b=sqr root of 126

b=11.31

hope it ! (btw im in connections academy to, good luck! )

graphs that are inverses of each other are graphs where their slopes are reciprocals of each other for example say you have an original equation of y=2x. the inverse of that graph would be y=-1/2(x). also when you see a graph where the original and the inverse is graphed the angle around intersection is 90 degrees.