(5r + ⅕ )² when r=0
Please somebody help me, I've been struggling with this for way too, long.

what are the answear choices to the question.

step-by-step explanation:

26

step-by-step explanation:

you can use a^2+ b^2=c^2

step-by-step explanation:

to determine whether a given function is even, we simply substitute x with -x in the expression. if the result after simplification is identical to the original equation, then the function is said to be even other wise odd.

f(-x) = (-x)^2 - (-x) + 8

      = x^2 + x +8

the resulting function is not identical to the original one;

f(-x) ≠ f(x)

therefore, f(x) is not an even function