Suppose a plane intersects a cube through three intersecting edges. How can you ensure that the triangular cross section is an equilateral triangle? a. the corner of the cube can be sliced off such that the three vertices of the triangle are at the same distance from the corner of the cube.

b. the corner of the cube can be sliced off such that the two vertices of the triangle are at the same distance from the corner of the cube.

c. the corner of the cube can be sliced off such that the plane intersects the base.

d. the corner of the cube can be sliced off such that the plane is perpendicular to the base.

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

i need a picture

step-by-step explanation:

the answer would be 44.79

plz mark brainliest

step-by-step explanation:

step-by-step explanation:

the ratio of red paint to blue paint is always 9/7. that means that, whatever x's value, (4x+12)/(4x-4) has that same ratio. so, set up an equation and cross-multiply to solve for x:

9/7 = (4x+12)/(4x-4)

9(4x-4) = 7(4x+12)

36x - 36 = 28x + 84

8x - 36 = 84

8x = 120

x = 15