A quadratic relation has zeros at 3 and –5. The parabola goes through the point (2, –14). What is the equation of the parabola in standard form?

Step-by-step explanation:

we are given the zeros and a point where it goes through of a quadratic equation

remember that when the roots are given then the function should be

where a is the leading coefficient and x1 and x2 are the roots

substitute:

simplify:

now the given point tells us that when x is 2 y is -14 therefore by using the point we can figure out a

substitute:

simplify parentheses:

simplify multiplication:

divide both sides by -7:

altogether substitute:

since it want the equation y should be

recall quadratic equation standard form:

so simplify parentheses:

distribute:

hence,

the equation of the parabola in standard form is 2x²+4x-30=0

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .