Find the equation of the line perpendicular to the line 6y-18x=12 that pases through the point (0, -5)

y = -x/3 -5

Step-by-step explanation:

when two lines are perpendicular, the relation between the slopes of the lines m1 and m2

m1m2 = -1

The general equation of a line is given as

y = mx + c where m is the slope and c is the intercept

Considering the given equation

6y-18x=12

6y  = 18x + 12

Divide through by 6

y = 3x + 2

comparing with y = mx + c,

m = 3

hence the slope of the perpendicular line m2

= -1/3

Given that the line passes through the point (0, -5)

Using the equation y - y1 = m(x - x1) to find the equation

y - - 5 = -1/3(x - 0)

y + 5 = -x/3

y = -x/3 -5

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6

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step-by-step explanation: