A car salesman sold three hybrid cars last week. The cars come in red, white, and black. A sale is listed as RWB if a red car was sold first, a white was sold second, and a black car was sold third.

A list of all possible outcomes is shown. Each outcome has equal probability.

{RRR, RRW, RRB, RWR, RWW, RWB, RBR, RBW, RBB, WWW, WWR, WWB, WRR,

WRB, WRW. WBR, WBB, WBW, BBB, BBR, BBW, BWR, BWW, BWB, BRW, BRR, BRB)

What is the probability that the cars sold last week included a white car or the first car sold was red?

23 / 27

Step-by-step explanation:

Total possible outcomes :

{RRR, RRW, RRB, RWR, RWW, RWB, RBR, RBW, RBB, WWW, WWR, WWB, WRR, WRB, WRW. WBR, WBB, WBW, BBB, BBR, BBW, BWR, BWW, BWB, BRW, BRR, BRB) = 27

Required outcome : 23

{RRR, RRW, RRB, RWR, RWW, RWB, RBR, RBW, RBB, WWW, WWR, WWB, WRR, WRB, WRW. WBR, WBB, WBW, BBW, BWR, BWW, BWB, BRW) = 23

Required outcome / Total possible outcomes

= 23 / 27

y=20x

: )

hope this

asnwer is (g o h o f)(x) = 2x - 6/x + 7

step-by-step explanation:

given,

f(x) = x - 3/x

g(x) = x + 3

h(x) = 2x + 1

we need to find : (g o h o f)(x)

we can write (g o h o f)(x) = g[ h{ f(x) } ]

so first we find h{f(x)}

h{f(x)} = f(x) + 3 = (x - 3/x) + 3

h{f(x)} = x - 3/x + 3

now we find g[ h{ f(x) } ].

g[ h{ f(x) } ] = g(x - 3/x + 3)       {plug h{f(x)} = x - 3/x + 3 in g[h{f(x)}] }

g(x - 3/x + 3) = 2 (x - 3/x + 3) + 1

                    = 2x - 6/x + 6 + 1

                    = 2x - 6/x + 7

hence we get (g o h o f)(x) = 2x - 6/x + 7