The dollar value of a car is a function, f, of the number of years, t, since the car was purchased. The function is defined by the equation f(t)=12,000(3/4)^t. A. How much was the car worth when it was purchased? Explain how you know.
B. What is f(2)? What does this tell you about the car?
C. About when was the car worth $6,000? Explain how you know.

1.) 12000

2.) 6750

3.) 2.41

Step-by-step explanation:

Given the Equation :

f(t)=12,000(3/4)^t. ; where, t = time ; f(t) = worth of car at time, t

When, car was purchased, t = 0

t = 0

f(0) = 12000(3/4)^0

= 12000 * 1

= 12000

2.)

f(2) ; this mean the worth of the car after 2 years :

f(2)=12,000(3/4)^t.

12000(3/4)^2

12000 * 0.5625

= 6750

When car will be worth 6000

f(t) = 6000

f(t)=12,000(3/4)^t.

6000 = 12,000(3/4)^t

6000 / 12000 = (3/4)^t

1/2 = (3/4)^t

Take the log of both sides :

Log(0.5) = log(0.75)^t

log(0.5) = tlog(0.75)

- 0.301029 = - 0.124938t

t = - 0.301029 / - 0.124938

t = 2.4094

t = 2.41 years

answer is 12345678900987654321234567890987654321

step-by-step explanation:

60.9774

step-by-step explanation:

because when you add 47.6 plus 7.32 equals 54.92

and when you add .0574 + 6= 6.0574

and when you add 54.92 and 6.0574 you get the answer of 60.9774.

plzz mark brainlest last one got deleted. cause i didn't explain it but i did but i understand what the mod meant