Which of the following describes the end behavior of
f(x) = (1/2)^x

as x approaches infinity, f(x) approaches 0

as x approaches -infinity, f(x) approaches infinity

Step-by-step explanation:

we can observe that 1/2 < 1 and since it's being exponentiated, the f(x) gets smaller and smaller as x gets bigger.

For example, f(0) = 1, f(1) = 1/2, f(2) = 1/4

so, as x approaches an infinitely large number, f(x) gets closer and closer to zero.

this is the opposite as x approaches a negatively large number. following exponential rules, 1/2^(x) = 2^x for all x < 0. therefore as x approaches negative infinity, f(x) approaches infinity.

in this case, f(-1) = 2, f(2) = 4, f(3) = 8

x=-2

infinite number of lines, so there is an infinite number of equations.

step-by-step explanation:

there are an infinite number of line that passes through the point (-2,5)

x=-2   is one line that passes through the point

y = 5 is another line that passes through the point

(these two lines are perpendicular to each other).

since the number of   numbers are infinite and the slope is the ratio of two numbers,(change in y over change in x) we can have an infinite number of slopes.     our only condition is that it passes through the point (-2,5)

idk

step-by-step explanation: