A football is kicked at an angle of 60 with initial velocity of 80 ft./s. approximately how far will the ball travel horizontally before it hits the ground? 4ft.

13ft

75ft

173ft

75ft

Step-by-step explanation:

We are to find the maximum height reached by the ball. This is expressed as;

H = u²sin²Ф/2g

u is the initial velocity = 80 ft./s.

Ф is the angle = 60degrees

g is the acceleration due to gravity = 32ft/s

Substitute

H =80²sin²60/2(32)

H = 6400sin²60/64

H = 100 (0.8660)²

H = 100*0.749956

H = 74.9956

H ≈ 75ft

Hence the ball has travelled 75ft apprximately

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length