ABCD IS a parallelogram. Prove that A=C

∠DAC=∠BCA (Alternate angle, AD∥BC)∠DAC=∠BCA (Alternate angle, AD∥BC)in two triangles∠DAC=∠BCA (Alternate angle, AD∥BC)in two trianglesAC is common side∠DAC=∠BCA (Alternate angle, AD∥BC)in two trianglesAC is common sideand ∠BAC=∠DCA (Alternate angle, AB∥DC)∠DAC=∠BCA (Alternate angle, AD∥BC)in two trianglesAC is common sideand ∠BAC=∠DCA (Alternate angle, AB∥DC)so two angle and one side is common∠DAC=∠BCA (Alternate angle, AD∥BC)in two trianglesAC is common sideand ∠BAC=∠DCA (Alternate angle, AB∥DC)so two angle and one side is commonso, ΔADC and ΔABC is congruent.