In Circle YmAD = 68° and mBC = 156. Find mZ1

m<1 = 112°

Step-by-step explanation:

Given:

Arc BC = 156°

Arc AD = 68°

Required:

m<1

Solution:

m<1 = ½(arc BC + arc AD) => based on intersecting chords angle measure theorem

Substitute

m<1 = ½(156° + 68°)

m<1 = ½(224)

m<1 = 112°

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

spinning a 1, 2, or 3. option d.

step-by-step explanation: when spinning a number graph up to 4, and aiming for any number less than 3, that automatically eliminates the number 4. now you have two numbers to spin on that are less than 3, but the number 3 is included in this question because it's no greater of an number than itself. i hope this you : )