A man drops a ball from the top of a 300 foot cliff. The height of the falling ball is modeled by h(t)=-16t2+300 where h is in feet and t is in seconds. How long does it take for the ball to be 44 feet above the ground?

The ball reaches 44 ft above the ground after 4 sec.

Step-by-step explanation:

Set h(t)=-16t^2+300 equal to 44 feet and solve for time, t.  Indicate exponentiation with " ^ "

-16t^2 + 300 = 44 becomes

-16t^2 + 256 = 0, or 16t^2 = 256.  Then, taking the square root of both sides, we get:

4t = 16, or t = 4 sec.  The ball reaches 44 ft above the ground after 4 sec.

1.0

step-by-step explanation:

simplifying

5(x + -6) = 2(x + 3)

reorder the terms:

5(-6 + x) = 2(x + 3)

(-6 * 5 + x * 5) = 2(x + 3)

(-30 + 5x) = 2(x + 3)

reorder the terms:

-30 + 5x = 2(3 + x)

-30 + 5x = (3 * 2 + x * 2)

-30 + 5x = (6 + 2x)

solving

-30 + 5x = 6 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-30 + 5x + -2x = 6 + 2x + -2x

combine like terms: 5x + -2x = 3x

-30 + 3x = 6 + 2x + -2x

combine like terms: 2x + -2x = 0

-30 + 3x = 6 + 0

-30 + 3x = 6

add '30' to each side of the equation.

-30 + 30 + 3x = 6 + 30

combine like terms: -30 + 30 = 0

0 + 3x = 6 + 30

3x = 6 + 30

combine like terms: 6 + 30 = 36

3x = 36

divide each side by '3'.

x = 12

simplifying

x = 12

this should .