Line AC intersects line EB at point F. Ray FD extends from point F. Determine the measures of ∠EFD and ∠CFD.

see below

Step-by-step explanation:  5 25  7 26

∠AFE is 85°  so ∠EFC will equal 180° - 85°  = 95°

remember if a right angle is 90° and two right angles is 180° which is just the angle of a line

now we need to solve for x in the following equation

6x - 20 + 2x + 19 = 95

       8x - 1    = 95

   8x - 1 + 1  =  95 +1

           8x  =  96

      8x / 8  = 96 / 8

             x  =  96/8

             x  =  12

now use  x = 12 to solve for ∠EFD and ∠CFD

∠EFD  =  6x - 20  

∠EFD  =  6(12) - 20

∠EFD =  52°

∠CFD  =   2x + 19  

∠CFD =   2(12) + 19

∠CFD =    43°

i think it would be 42cm