![\sqrt[3]{\frac{-729}{216} } = \sqrt[3]{\frac{9*9*9*}{6*6*6} } = (\frac{9^3}{6^3})^{\frac{1}{3} } = \frac{9}{6} = \frac{3}{2}](/tpl/images/1343/8577/67d79.png)
J need help w number 4 algebra to have to show all work
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Mathematics, 22.06.2019 00:10, arianna23717
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