What is the expected value for the binomial distribution below?

1/3125
4/625
32/625
128/625
256/625
1024/3125

999.224

Step-by-step explanation:

Expected value = Summation of (x•px)

px is addressed as pdf (probability distribution function)

x px. x•px

1. 1/3125. 1/3125

20. 4/625. 16/125

160. 32/625. 1024/125

640. 128/625. 16384/125

1280. 256/625 65536/125

1024. 1024/3125. 335.544

total:. 1. 999.224

taking my pdf as x/3125

false

step-by-step explanation:

4y - 6 + 4y^2 - 9

before simplifying this contains 4 terms

after simplifying

4y -15 + 4y^2

it contains 3 terms

arrange the equations with like terms in columns.

analyze the coefficients of x or y.

add the equations and solve for the remaining variable.

substitute the value into either equation and solve.

check the solution.

step-by-step explanation: