Solve the following inequality using both the graphical and algebraic approach: 5 minus x less-than 2 (x minus 3) + 5 Graph A On a coordinate plane, a line goes through (0, 5) and (5, 0). Another line goes through (negative 2, negative 4) and (2, 3). The lines intersect at (2, 3). Graph B On a coordinate plane, a line goes through (0, 0) and (2, negative 6). Another line goes through (0, negative 8) and (2, negative 6). a. x less-than 2 Graph A b. x greater-than 2 Graph A c. x less-than 2 Graph B d. x greater-than 2 Graph B

arithmetic sequence

step-by-step explanation:

given that a sequence has terms as

19, 15, 11,

this is represented on a graph

the pattern indicates that the sequence is an arithmetic sequence with i term

a=19 and common difference d =-4

any general term

thus the sequence is reduced by 4 for each successive term starting from 1 and nth term is

24-5n.

first negative term would start after 5th term

5th term =24-25< 0

from 5th term onwards the sequence would be negative.

goog may be able to you find that answer

cheater

step-by-step explanation: