Gerard tales 30 minutes to run 6000 metres at a steady speed. How long would he take to run 1 kilometre at the same steady speed

He would take 0.0833 hour  or 5 mins

Step-by-step explanation:

Given that Gerard ran a  6000 metres in 30 minutes, Speed becomes

Speed =distance / time

But time  to hours becomes  30/ 60=1/2=0.5hr

and meters to kilometres becomes 6000/1000=6 km

Speed =6/0.5 =12 km/h

Now if he runs 1 kilometre at same speed of 12 km/h . he will take

Time =distance/ Speed

Time =1/12=0.0833 hour  Changing to mins becomes 0.08333 x 60=5 mins

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

you would have to sell 24 bracelets.

step-by-step explanation:

84/3.5 = 24