In a 3-digit number, the hundreds digit is one more than the ones digit and the tens digit is twice the hundreds digit. If the sum of the digits is 11, find the number.

362

Step-by-step explanation:

Let the ones digit equal x. If the ones digit is one, then the hundreds digit is one more than it or x + 1. And, since the tens digit is twice the hundreds digit, you can say it is 2(x + 1) or as simplified: 2x + 2. Now, we are given the sum of the digits is 11, so if we add all of them, they should be equal to 11:

x + x + 1 + 2x + 2 = 11

We can combine like terms:

4x + 3 = 11

4x = 8

x = 2

So, the ones digit is 2. Since the hundreds digit is one more, it's 3. And because the tens is twice the hundreds, it's 6. The number is 362.

362

Step-by-step explanation:

the answer is 363 bcz 3*2=6.3-1 is 2 and 6+3+2 os 11.This satisfys all three condisions.Now the equations if x is the hundreths digit is :x+(2x)+(x-1)=11.

I hope this helps

maybe showing the graph would

step-by-step explanation:

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