Find the second, fourth, and eleventh terms of the sequence A(n) = 5 + (n - 1)(-3)​

2nd: 2

4th: -4

11th: -25

Step-by-step explanation:

When you substitute a number into the equation you get that number term. So, if you substituted in 1, you get the first term. To find the second term, you substitute in 2:

A(2) = 5 + (2 - 1)(-3)

A(2) = 5 + (1)(-3)

A(2) = 5 - 3

A(2) = 2

To get the 4th term you substitute in 4:

A(4) = 5 + (4 - 1)(-3)

A(4) = 5 + (3)(-3)

A(4) = 5 - 9

A(4) = -4

And we do the same for the 11th term:

A(11) = 5 + (11 - 1)(-3)

A(11) = 5 + (10)(-3)

A(11) = 5 - 30

A(11) = -25

step-by-step explanation: a reaction is first order. if the initial reactant concentration is 0.0200 m, and 25.0 days later the concentration is 6.25 x 10-4 m, then its half-life is:

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step-by-step explanation:

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