Solve the equations for x:
x^2+nx-mx-nm=0

x =  [(m - n +/-√ (n^2 + m^2 + 2nm)]/2.

Step-by-step explanation:

x^2+nx-mx-nm=0

x^2 + (n - m)x - nm = 0

Using the quadratic formula:

x = [-(n - m) +/- √((n - m)^2 - 4*-nm)) / 2

= [(m - n +/- √ (n^2 + m^2 - 2nm + 4nm)]/2

=   [(m - n +/-√ (n^2 + m^2 + 2nm)]/2

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).

i'm not entirely sure

step-by-step explanation:

if you ask home depot or lowe's they might be able to you out